The C=O bond is highly polarized toward the oxygen. This is primarily an effect of the oxygen atom's electronegativity; however, resonance effects accentuate this over what is seen in an ether: One way we can further understand the reactivity uses the results of molecular orbital calculations. The highest occupied molecular orbital (HOMO) shows where electrophiles will attack; the lowest unoccupied MO will show where nucleophiles will attack. Alternatively, the relative charge distribution diplayed in an electrostatic potential map can tell us similar things. | |
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A simplified diagram emphasizes the C=O bond: Load LUMO Load HOMO White backgrounds Black backgrounds |
The HOMO and LUMO of the carbonyl group in cyclohexanone (click the link to visualize). Red and blue signify only different mathematical signs for the MO wavefunction. Both of these MOs mix in parts of the rest of the molecule (as all molecular orbitals do), but you can see three distinguishing features:
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Load ESP surface Now load the electrostatic potential map for cyclohexanone (click link to load). Blue = positive potential; Red = negative potential. |
The net effect of all of the MOs working together (though consistent with the HOMO & LUMO we illustrate) is to have electron density build up on oxygen, and decreased elsewhere in the molecule. Note especially the difference between axial and equatorial hydrogens on the alpha position--we'll see this is important in later chapters.
The most important reactivity feature of the carbonyl group is that (electon-rich) nucleophiles attack at the carbonyl carbon to form new bonds. |
Now, look at what happens when an (electron-poor) electrophile reacts. H+
bonds to the oxygen, accentuating the positive character of the carbonyl carbon,
particularly when compared to the rest of the molecule. This accelerates attack of a nucleophile. Note when you load the ESP map, that the molecule as a whole is more blue (positive), centered on the added proton and the carbonyl carbon. Any Lewis acid has this effect of binding to oxygen, and activating the carbonyl carbon for nucleophilic attack. |
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Aldehydes are generally more reactive than ketones to nucleophilic addition; a quick
look at the ESP map confirms that the carbonyl is slightly more positive at carbon. (Why, do you think?) Also, the steric congestion is far less at an aldehyde than a ketone. |
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