The Hamiltonian (10 minutes)

$$H=- \: \vec{\mu} \cdot \vec{B}=- \: \gamma \, \vec{S} \cdot \vec{B} \; \; .$$

$$\hat{H}=- \: \gamma S_{z} B_{z} \; \; .$$

Although this Hamiltonian isn't very interesting because it is proportional to an operator we already know ( $\;S_{z}\;$ ) and because it depends on the magnitude of the external magnetic field, it is a very useful operator. The eigenvalues of the matrix for the Hamiltonian will be the energy values that you can measure. Note that the difference in the energy eigenvalues is more important than the values themselves since we are more commonly interested in the difference of energy levels.

$$\pm \gamma B_{z} \frac{\hbar}{2}$$

should be found.