Examples of Second Order ODE

Phenomena in many disciplines are modeled by first-order differential
equations. Some examples include

Mechanical Systems Mechanical Systems/Vibrations

Newton's second law asserts that the sum of the external forces acting on
an object at any instant in time is equal to the product of the object's mass
and acceleration. This has far reaching implications for ODE's.

Consider a mass attached to a spring that is allowed to move in a straight
line in the horizontal direction. Let x(t), v(t), and a(t) denote the position,
velocity, and acceleration, respectively, of the mass. We assume that x=0
is the equilibrium position of the mass. Hooke's law asserts that the force
exerted on the mass by the spring is F(t)=-kx(t), where k is the spring
constant. Newton's second law states:

Mass times Acceleration = Sum of External Forces.


Using the fact that a(t)=x''(t) we obtain the equation

displaymath38

This is a linear second-order ode. It is accompanied by the initial
position x(0) and the initial velocity x'(0).

Notice that according to Hooke's law the force exerted by the spring
depends linearly on the position x(t). In many applications the force depends
nonlinearly on x(t). One example is Duffing's model. The differential
equation is

displaymath40

Here e is a positive constant. This is an example of a nonlinear
second-order ode.

Finally, suppose that there is damping in the spring-mass system. Damping
might be provided by a dashpot that exerts a continuous force that is
proportional to the velocity (F(t)=-cv(t), where c is a constant). The total
force is a sum of force due to the spring and the damping. The differential
equation is

displaymath42

Electrical Circuits

An RLC circuit consists of a resistor, an inductor, and capacitor in series
with a voltage source. Let us assume that the resistance is R, the inductance
is L, the capacitance is C, and the electromotive force is E(t). Let I(t) denote
the current in the circuit and Q(t) denote the charge on the capacitor. The
charge and current are related by Q'(t)=I(t). Basic circuit analysis states that
the sum of the voltage drops across the circuit elements equals the applied
voltage. The voltage drop across the inductor is LI'(t). The voltage drop
across the resistor is RI(t). The voltage drop across the capacitor is Q(t)/C.
Hence, the differential equation is LI'(t)+RI(t)+Q(t)/C=E(t). Differentiating
this equation we get:

displaymath44

This is an example of a linear second-order ode. To completely solve
this problem the initial current I(0) and its derivative I'(0) must be specified.

One-Dimensional Free Fall Motion

Suppose that a particle initially at height y_0 is thrown straight upward
with velocity v_0. Let s(t) denote the particle's height, v(t) the particle's
velocity, and a(t) the objects acceleration at time t. If air resistance is neglected,
then by Newton's second law we have ma(t)=-mg. Using the fact that
a(t)=s''(t) and eliminating the mass, we obtain the equation

displaymath50

The initial position s(0) and initial velocity s'(0)=v(0) must be specified.
This is linear second-order ode.

Now suppose that air resistance is proportional to velocity.

displaymath52

This is another example of a linear second-order ode.


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