(ref: Mohrig, Secs. 21.7-21.11, pp. 325-344)
Once you collect a spectrum, the real work begins. Spectra of organic compounds have
two general areas:
4000-1500 cm-1 |
1500-400 cm-1 |
|
The Functional Group Region Peaks in this region are
characteristic of specific kinds of bonds, and therefore can be used to identify whether a
specific functional group is present. |
The Fingerprint Region
Peaks in this region arise from complex deformations of the molecule. They
may be characteristic of molecular symmetry, or combination bands arising from multiple
bonds deforming simultaneously.
|
A
word about units. Most spectra using electromagnetic radiation are presented
with wavelength as the X-axis. Originally, IR spectra were presented in units of
micrometers. Unfortunately, a linear axis in micrometers compresses the region of
the spectrum 10-15 μm) that usually has the largest number of
peaks. One could rectify this by presenting the speectrum on a linear scale vs.
frequency (Hz), but the magnitude is unwieldy (10 μm = 3 x 1013
Hz). A different measure, the wavenumber, is given the unit cm-1.
The relationship can be derived by the relationship
ν (cm -1)= 10,000/λ
(μm) |
The two regions of the spectrum overlap to a degree.
(In fact, one always finds overlap between different regions of any spectrum; these
designations are "guideposts" to help you orient yourself.) For example,
carbon-chlorine bonds appear at around 800 cm-1, and C-O single bonds appear at
around 1200-1300 cm-1. Also, benzene rings show "overtones" in
the 1500-1700 cm-1 region, even though these arise from complex ring
deformations.
The normal way to approach interpretation of an IR spectrum is to
examine the functional group region to determine which groups might be present, then to
note any unusually strong bands or particularly prominent patterns in the fingerprint
region. Finally, if you think you have identified the compound (usually you need
additional information) you can compare the spectrum with a reference. Matching the
fingerprint region is a very rigorous test.
Look at the page about molecular vibrations and see this relationship for yourself.
|
Some important IR-active functional groups, and examples of spectra.
Identify the peak(s) within the particular functional group region.
C-H
3000-3100 cm-1 (sp2)
2800-3000 cm-1 (sp3)
1-Hexene:
|
C=O
1600-1800 cm-1
Carboxylic Acids: 1650-1700
Esters: 1740-1750
Aldehydes: 1720-1750
Ketones: 1720-1750
Amides:1650-1715
Benzaldehyde:
|
O-H
(alcohol)
3300-3600 cm-1
Monomeric forms (i.e., gas phase): sharp.
H-bonding leads to broadening in solution.
1-Methylcyclopentanol:
|
O-H
(carboxylic acids)
2400-3000 cm-1
Very broad, medium intensity
Benzoic Acid:
|
C≡C
C≡N
2200-2100 cm-1
Usually weak; maybe not visible
in internal alkynes.
Nitriles are quite strong.
Phenylethyne:
Hexanenitrile:
|
C-O
1200-1300 cm-1.
Often difficult to assign,
depending on fingerprint region.
Ethyl Acetate (both C=O and C-O visible):
|
N-H
3400 cm-1.
Usually sharper than O-H. Two peaks indicate NH2; a single peak is NH (secondary amine/amide). Tertiary amines/amides have no N-H bond and so show no peak.
n-Butylamine:
Acetamide:
|
A final word about symmetry.
Molecular vibrations give rise to IR bands only if they cause a change in the dipole
moment of the molecule. (This comes out of the quantum mechanics of molecular
absorption of energy, so we aren't concerned too much with why, yet.) If a stretch
does not change the dipole moment, there won't be any IR band. This is why O2
and N2 in the atmosphere don't show any IR bands. CO2,
however, has a stretch where one O moves in and the other moves out:
Thus we see this band at 2400 cm-1.
Last updated: 01/17/2014
|