Addition of HOBr to a symmetrical alkene is a stereospecific reaction: different isomers of the alkene lead to different isomers of product. Convince yourself of this by examining the outcome.
Each reactant forms a bromonium ion.
cisMeBr.pdb | transbromonium.pdb |
Each bromonium ion is symmetric, and can be attacked at either ring carbon. However, the trans-dimethylbromonium ion is chiral; both enantiomers are formed in equal amounts.
The cis isomer leads to two enantiomeric products, the (2R, 3R) and the (2S, 3S):
(Which is which? Assign the configurations.)
cisbromohydrin1.pdb | cisbromohydrin2.pdb |
The trans isomer leads to a slightly different situation, the pair is now (2R, 3S) and (2S, 3R):
trbromohydrin1.pdb | trbromohydrin2.pdb |
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Last updated: -5/07/2014
Comments to K. Gable