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--- hw3 [2016/04/16 10:25] – [Journal reading (5 pts)] janet
+++ hw3 [2016/04/16 11:53] – [Landauer to Drude (10 pts)] janet
@@ Line 21: / Line 21: @@
 $$R = {h \over {2{e^2}}}{L \over {{\ell _{ph}}}}$$
-**c)** Show that the the above result is equivalent to the Drude formula, within a factor of 2, if we assume a free electron dispersion relation $E = {{{\hbar ^2}{k^2}} \over {2m}}$.
+**c)** Show that the above result is equivalent to the Drude formula, within a factor of 2, if we assume a free electron dispersion relation $E = {{{\hbar ^2}{k^2}} \over {2m}}$.
 $${\rho _{1d}} = {m \over {{n_{1d}}{e^2}{\tau _{e - ph}}}}$$