(Last update: 2/28/19)
Page 26, first two full paragraphs: The unit conversions with $c$ are backward. The best fix is to swap “…measure distance in seconds” with “… measure time in meters”, and probably also swap the two subsequent sentences (each starting with “Thus,”) in their entirety.
Pages 30–35: The examples in §5.5 assume that both vectors lie on the same branch of the hyperbola. For instance, all timelike vectors are assumed to be future-pointing. In most cases, this restriction can be removed by replacing $\cosh\alpha$ by $\pm\cosh\alpha$.
Page 38, first full paragraph, line 9: $\beta$ is an angle, not a distance, so “$\beta$ is precisely” should be “$\rho\beta$ is precisely”.
\[ \tan\theta' = \frac{u_y'}{u_x'} = \frac{u_y}{u_x-v} = \frac{\tan\theta}{1-\frac{v}{u\cos\theta}} = \frac{u\sin\theta}{u\cos\theta-v} \]
\[\Partial{F^{\mu\nu}}{x^\nu} = \frac{1}{c}\Partial{F^{\mu0}}{t} + \Partial{F^{\mu1}}{x} + \Partial{F^{\mu2}}{y} + \Partial{F^{\mu3}}{z}\]
\[ \frac12 F_{\mu\nu} F^{\mu\nu} = -\frac{1}{c^2}\,{|\EE|}^2 + |\BB|^2 = - \frac12 G_{\mu\nu} G^{\mu\nu} \]
\[d_H(U,V) = \rho\,\cosh^{-1}\left(-\frac{\uu\cdot\vv}{\rho^2}\right)\]
\begin{align*} d_H(U,V) &= \rho\,\cosh^{-1}(-\sinh\alpha\sinh\beta+\cosh\alpha\cosh\beta) \\ &= \rho\,\cosh^{-1}(\cosh(\beta-\alpha)) \\ &= \rho\,|\beta-\alpha| \end{align*}
\[ X + iY = -2\frac{i(x+iy)+\rho}{(x+iy)+\rho\,i} \]
\[ ds^2 = \frac{4\,\rho^4\left(dx^2+dy^2\right)}{(\rho^2-x^2-y^2)^2} = \rho^2\>\frac{dX^2+dY^2}{Y^2} \]
Page 115, last paragraph: The closed interval $[0,\pi/2]$ should be the half-open interval $(0,\pi/2]$.
Pages 120–125: The points $A$ and $B$ have been interchanged here compared to §4.3. One fix is to interchange $A$ and $B$ throughout §4.3, including in Figure 4.2, also in Figure 5.2, and finally in §6.2.
Page 123, Equation (15.24): $A$ should be $B$ in the derivative; the full equation should read $B^\perp = (\rho\,\cosh\beta,\rho\,\sinh\beta)=\frac{dB}{d\beta}$.