In the Interlude, we learned that mixed partial derivatives are the same, regardless of the order in which we take the derivative, so $$\left(\frac{\partial \left(\frac{\partial f}{\partial x}\right)_y}{\partial y}\right)_x=\left(\frac{\partial \left(\frac{\partial f}{\partial y}\right)_x}{\partial x}\right)_y$$ $$\frac{\partial^2 f}{\partial x \partial y}=\frac{\partial^2 f}{\partial y \partial x}$$ In the Interlude we found a Maxwell relation from the energy conservation law: $$dU = F_1dx_1 + F_2dx_2$$ $$\left(\frac{\partial \left(\frac{\partial U}{\partial x_1}\right)_{x_2}}{\partial x_2}\right)_{x_1}=\left(\frac{\partial \left(\frac{\partial U}{\partial x_2}\right)_{x_1}}{\partial x_1}\right)_{x_2}$$ $$\left(\frac{\partial F_1}{\partial x_2}\right)_{x_1}=\left(\frac{\partial F_2}{\partial x_1}\right)_{x_2}$$ As you know, in thermodynamics, partial derivatives are often physically measurable quantities. In such a case, their derivatives are also be measurable quantities that we often care about.

In your groups, consider mixed partial derivatives of the thermodynamic potential assigned to you, to derive a Maxwell relation. [GROUP]