Geometry of General Relativity book:content
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2020-01-26T14:21:56-08:00Geometry of General Relativity
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First and foremost, I thank my wife and colleague, Corinne Manogue, for discussions and encouragement over many years. Her struggles with the traditional language of differential geometry, combined with her insight into how undergraduate physics majors learn --- or don't learn --- vector calculus have been a major influence on my increased use of differential forms and orthonormal bases in the classroom.text/html2014-04-23T20:49:00-08:00book:content:bang
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Slightly rewriting Einstein's equation for the Robertson-Walker metric, as given in~(ss)Robertson-Walker Metrics, we obtain first \begin{equation} \frac{\dot{a}^2+k}{a^2} = \frac{8\pi\rho+\Lambda}{3} \end{equation} and then \begin{equation} \frac{2\ddot{a}}{a} = \Lambda - 8\pi p - \frac{\dot{a}^2+k}{a^2} = \frac23 \Lambda - \frac{8\pi}{3} \left(\rho+3p\right) \end{equation} A physically realistic model that is not empty will have strictly positive energy density $(\rho>0)$ and nonnegative pr…text/html2014-04-23T21:18:00-08:00book:content:bending
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Recall from previous sections that the null geodesics of the Schwarzschild geometry satisfy \begin{align} \dot\phi &= \frac{\ell}{r^2} \\ \dot{t} &= \frac{e}{\left(1-\frac{2m}{r}\right)} \\ \dot{r}^2 &= e^2 - \left( 1-\frac{2m}{r} \right) \frac{\ell^2}{r^2} \label{ngeo} \end{align} Setting \begin{equation} u = \frac{1}{r} \end{equation} we have \begin{equation} \dot{r} = -\frac{1}{u^2} \dot{u} = -r^2 \dot{u} = -\ell \> \frac{\dot{u}}{\dot\phi} = -\ell \> \frac{du}{d\phi} \end{equation} so …text/html2013-12-18T09:17:00-08:00book:content:birkhoff
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Birkhoff's Theorem states that the Schwarzschild geometry is the only spherically symmetric solution of Einstein's equation. This result is remarkable, in that the Schwarzschild geometry has a timelike symmetry (Killing vector), even though this was not assumed; spherically symmetric vacuum solutions of Einstein's equation are automatically time independent! We outline the proof of Birkhoff's Theorem below.text/html2013-12-19T11:22:00-08:00book:content:books
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\begin{itemize}\item Edwin F. Taylor and John Archibald Wheeler, Exploring Black Holes, Addison Wesley Longman, 2000. An elementary introduction to the relativity of black holes, using
line elements. Not easy to read, but worth it.
\item James B. Hartle, Gravity, Addison Wesley, 2003. An ``examples first'' introduction to general relativity, discussing
applications of Einstein's equations before presenting the mathematics behind
the equations.text/html2013-12-18T09:18:00-08:00book:content:charge
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text/html2013-12-17T21:54:00-08:00book:content:circle
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Figure 1: Defining the (circular) trigonometric functions via a circle.
What is the fundamental idea in trigonometry? Although often introduced as the study of triangles, trigonometry is really the study of circles.
One way to construct the trigonometric functions is as follows: \begin{itemize}\item Draw a circle of radius $r$, that is, the set of points at constant distance $r$ from the origin. \item Measure arclength $s$ along the circle by integrating the (square root of the) line eleme…text/html2013-12-18T08:04:00-08:00book:content:conserve
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We have seen that the energy-momentum of a cloud of dust, according to an observer with 4-velocity $\vv$, is given by \begin{equation} \Tvec_{\vv} = \rho\,\uu \,(-\uu\cdot\vv) \end{equation} If the dust is moving at speed $v=\tanh\beta$ with respect to the observer $\vv$, then the 4-velocity $\uu$ of the dust takes the form \begin{equation} \uu = \begin{pmatrix} 1\\ \us\\ \end{pmatrix} \cosh\beta \label{ucomp} \end{equation} where we have introduced the notation $\us$ for the 3-velocity of t…text/html2013-12-18T08:11:00-08:00book:content:constcurv
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In any dimension and signature, it turns out there is a unique (local) geometry of constant (sectional) curvature, which can be classified by the value of the scalar curvature $R$. These three possibilities are illustrated for two dimensions with Euclidean signature in Figure~1, showing a plane (zero curvature), sphere (constant positive curvature), and Lorentzian hyperboloid (constant negative curvature), respectively. In each case, the surface is two-dimensional, even though the representa…text/html2013-12-18T08:11:00-08:00book:content:cosconst
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Einstein was not happy with some of the predictions of his theory, notably, as we will see in the next chapter, that the universe is expanding. He therefore looked for a way to modify his theory to permit a static universe.
There is in fact just one way to do so; the only other divergence-free geometric object (of the correct size, that is, with the correct number of components) is the line element itself! Using the fact that \begin{equation} {*}\sigma^i = \pm \sigma^j\wedge\sigma^k\wedge\sig…text/html2013-11-06T09:38:00-08:00book:content:cosmo
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Cosmology is, simply put, the study of the universe. Relativistic cosmology is the study of solutions of Einstein's equation which may represent the broad features of the universe as a whole.
One constraint on such models is the seemingly innocuous statement that the sky is dark at night. Why is this surprising? In a Euclidean universe with a uniform distribution of stars, both the density of matter and the apparent luminosity fall off as $1/r^2$. Thus, the perceived brightness of every thi…text/html2014-04-23T20:29:00-08:00book:content:cosprin
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Figure 1:A foliation of spacetime by hypersurfaces of constant cosmic time.
Figure 2:A foliation of spacetime by a family of observers.
Figure 3:In a spacetime that is both isotropic and homogeneous, the cosmic
observers are orthogonal to the cosmic surfaces.
The simplest cosmological models are based on the principle that the universe is the same everywhere. This principle is sometimes referred to as the cosmological principle, and can be thought of as an extreme generalization of the Cop…text/html2013-12-18T09:14:00-08:00book:content:divein
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We verify here that the divergence of the Einstein vector-valued 1-form $\GG$ vanishes, that is, that \begin{equation} d\gamma^i + \omega^i{}_j\wedge\gamma^j = 0 \label{diveineq} \end{equation} where \begin{equation} \gamma^i = \frac12 \epsilon_\ell{}^{ijk} \,\Omega_{jk} \wedge \sigma^\ell \end{equation} as shown in~(ss)Components of the Einstein Tensor. Using the Bianchi identities and the structure equations to evaluate the first term, we have \begin{align} 2 &(d\gamma^i + \omega^i{}_j\wed…text/html2013-12-18T09:15:00-08:00book:content:divmet2d
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We now consider the general case, for which \begin{equation} d\rr = \sigma^i\,\ee_i \end{equation} Recalling that the Hodge dual of $\sigma^i$ satisfies \begin{equation} \sigma^i\wedge{*}\sigma^i = g(\sigma^i,\sigma^i)\,\omega \end{equation} we can write \begin{equation} {*}\sigma^i = \frac{1}{(n-1)!}\,\epsilon^i{}_{j...k}\,\sigma^j\wedge...\wedge\sigma^k \end{equation} where the $n$-index object $\epsilon_{ij...k}$ is the alternating symbol in $n$ dimensions, sometimes called the Levi-Civita s…text/html2013-11-05T17:55:00-08:00book:content:dust
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Let's summarize the discussion in the preceding section, but without the restriction to Minkowski space. Matter is described by the energy-momentum 1-forms \begin{equation} T^i = T^i{}_j\,\sigma^j \end{equation} which can be combined into a single vector-valued 1-form \begin{equation} \Tvec = T^i \ee_i \end{equation} Consider an observer with velocity vector $\vv$ satisfying \begin{equation} \vv \,d\tau = d\rr \end{equation} and drop the arrow to write as usual \begin{equation} v=\vv\cdot d\rr …text/html2014-04-30T21:24:00-08:00book:content:einstein
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As discussed in the previous sections, matter in general relativity is described by a vector-valued 1-form \begin{equation} \Tvec = T^i\,\ee_i \end{equation} where \begin{equation} T^i = T^i{}_j\,\sigma^j \end{equation} are the energy-momentum 1-forms. The components $T^i{}_j$ are (also) components of the energy-momentum tensor. We assume that the energy-momentum tensor is symmetric, that is, that \begin{equation} T_{ji} = T_{ij} \end{equation} which can also be expressed as the requirement th…text/html2013-12-18T09:14:00-08:00book:content:einsteinc
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As discussed in the previous sections, matter is described by the energy-momentum tensor, which we now write as \begin{equation} \Tvec = T^i{}_j \sigma^j \ee_i = {*}\tau^i \ee_i \end{equation} and conservation of matter requires that $\Tvec$ be divergence-free, that is, that \begin{equation} d{*}\Tvec = \zero \end{equation} Meanwhile, it turns out that there is a unique divergence-free vector-valued 1-form which can be constructed from the curvature, namely the Einstein tensor \begin{equation} …text/html2014-04-30T21:29:00-08:00book:content:einsteing
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In Newtonian theory, gravity is described by the gravitational potential $\Phi$. It can be shown that tidal acceleration in the $\uu$ direction is just the difference in the acceleration due to gravity at nearby points, which can be expressed as a directional derivative of the gravitational field, namely \[ -(\uu\cdot\grad)(\grad\Phi) \] More precisely, this expression describes the vector change in the displacement between two freely falling objects, which are (originally) separated in the $\u…text/html2014-04-23T20:51:00-08:00book:content:frw
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Current observations show that \begin{equation} \rho \gg p \end{equation} (in appropriate units!); the universe is presently ``matter dominated''. We therefore consider models with \begin{equation} p = 0 \end{equation} which are called Friedmann-Robertson-Walker models, or just Friedmann models.text/html2013-12-21T11:01:00-08:00book:content:fvac
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We first consider Robertson-Walker cosmologies that are also vacuum
solutions, that is, for which \begin{equation} \rho = 0 = p \end{equation} Friedmann's equation reduces to \begin{equation} \dot{a}^2 = \frac{\Lambda a^2}{3} - k \label{frwvac} \end{equation}text/html2014-04-30T21:46:00-08:00book:content:geodesics
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When is a curve ``straight''? When its tangent vector is constant. We have \begin{equation} \vv = \frac{d\rr}{d\lambda} = \dot\rr \end{equation} or equivalently \begin{equation} \vv\,d\lambda = d\rr = \sigma^i\ee_i \end{equation} so that the components of $\vv$ are given by \begin{equation} v^i d\lambda = \sigma^i \label{vcomp} \end{equation} Differentiating, we obtain \begin{align} d\vv = d(v^i \ee_i) &= dv^i \ee_i + v^i d\ee^i \nonumber\\ &= (dv^j + \omega^j{}_i v^i) \ee_j \nonumber\\ …text/html2013-12-18T08:00:00-08:00book:content:geodev
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Consider a family of geodesics, with velocity vectors of the form \begin{equation} \vv = \dot{\rr} = \Partial{\rr}{\tau} \end{equation}
Figure 1:A family of geodesics.
as shown in Figure~1. Since these curves are geodesics, their velocity vectors satisfy \begin{equation} \dot{\vv} = 0 \end{equation} Label the geodesics by some coordinate(s) $s$, and consider the separation vector \begin{equation} \uu = \rr' = \Partial{\rr}{s} \end{equation} between nearby geodesics. By construction, we have…text/html2015-04-18T10:53:00-08:00book:content:geodev2
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As before, let $\vv=\dot{\rr}$ denote the velocity vectors of a family of geodesics, and $\uu=\rr'$ the separation vector between them. Then along the geodesics we have \begin{align} \vv\,d\tau &= d\rr \\ v^k\,d\tau &= \sigma^k \end{align} and similar expressions hold along curves with tangent vector $\uu$, namely \begin{align} \uu\,ds &= d\rr \\ u^k\,ds &= \sigma^k \end{align}text/html2013-12-18T08:19:00-08:00book:content:gps
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There are three key ideas underlying Einstein's theory of general relativity: \begin{itemize}\item Principle of Relativity:
The principle of relativity originates with Galileo, and says that the results of experiments do not depend on relative (uniform) motion of observers. Einstein's contribution was to apply this principle to electromagnetism. Since the speed of light can be computed from the constants in Maxwell's equations, the speed of light must be independent of the observer. This pos…text/html2013-09-29T09:41:00-08:00book:content:gsr
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A spacetime diagram in special relativity is just a diagram drawn using hyperbola geometry. Vertical lines represent the worldline of an observer standing still (in the given reference frame). Horizontal lines represent a ``snapshot'' of time, according to that observer.text/html2014-04-23T21:04:00-08:00book:content:hubble
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In special relativity, light emitted by a moving observer at one frequency is received by a stationary observer at another frequency. This is the Doppler effect, which can be computed using Figure~1. In this case, the two heavy lines correspond to observers moving at different velocities, and the two lighter lines correspond to pulses of light, emitted by the moving observer (on the right), and received by the stationary observer (on the left). Simple (hyperbolic) triangle trigonometry can b…text/html2013-12-12T10:02:00-08:00book:content:hyperbola
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Figure 1: Defining the hyperbolic trigonometric functions via a (Lorentzian)
hyperbola.
We now apply the same procedure to Lorentzian hyperbolas rather than Euclidean circles, as illustrated in Figure 1. \begin{itemize}\item Draw a hyperbola of ``radius'' $\rho$, that is, the set of points at constant (squared) distance $r^2=x^2-t^2$ from the origin. \item Measure arclength $\tau$ along the hyperbola by integrating the (absolute value of the square root of the) line element. That is, inte…text/html2014-04-23T15:44:00-08:00book:content:kerr
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The Schwarzschild geometry can be regarded as a real slice of a complex geometry, where one can perform a complex rotation and consider the resulting real slice. The resulting line element, known as the (Boyer-Lindquist form of the) Kerr metric, describes a rotating black hole, and is given by \begin{align} ds^2 &= - \frac{\Delta}{\rho^2} \left(dt-a\sin^2\theta\,d\phi\right)^2 + \frac{\sin^2\theta}{\rho^2} \left( (r^2+a^2)\,d\phi-a\,dt \right)^2 \nonumber\\ &\qquad + \frac{\rho^2}{\Delta} d…text/html2014-04-24T16:18:00-08:00book:content:kruskal
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Figure 1: Kruskal geometry.
Since Kruskal-Szekeres coordinates $U$ and $V$ are well-defined at $r=2m$, we can use them to extend Schwarzschild geometry to $r<2m$. The maximally extended Schwarzschild geometry, also called the Kruskal geometry is obtained by extending the domains of $U$, $V$ as much as possible, and is shown in Figure~1.text/html2014-04-30T21:45:00-08:00book:content:line
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The fundamental notion in geometry is distance. One can study shapes without worrying about size or scale, but that is topology; in geometry, size matters.
So how do you measure distance? With a ruler. But how do you calibrate the ruler?
Figure 1:The infinitesimal version of the Pythagorean Theorem in rectangular
coordinates.text/html2014-04-23T20:07:00-08:00book:content:matter
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Figure 1:Equally spaced particles, moving uniformly to the right.
Figure 2:A spacetime diagram of equally spaced particles, moving uniformly to the
right.
Figure 3:Determining the spacing between moving particles, as seen by an observer
at rest. The dot denotes a right angle.
The 2-momentum of an object in (2-dimensional) Minkowski space moving at speed $v=\tanh\beta$ is given by \begin{equation} \bp = m\,\bu = \begin{pmatrix} E \\ p \\ \end{pmatrix} = \begin{pmatrix} m\,\cosh\beta \\ m\,…text/html2014-04-23T21:28:00-08:00book:content:mercury
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Recall from previous sections that the timelike geodesics of the Schwarzschild geometry satisfy \begin{align} \dot\phi &= \frac{\ell}{r^2} \\ \dot{t} &= \frac{e}{\left(1-\frac{2m}{r}\right)} \\ \dot{r}^2 &= e^2 - \left( 1-\frac{2m}{r} \right) \left( 1+ \frac{\ell^2}{r^2} \right) \label{tgeo} \end{align} Setting \begin{equation} u = \frac{1}{r} \end{equation} we have \begin{equation} \dot{r} = -\frac{1}{u^2} \dot{u} = -r^2 \dot{u} = -\ell \> \frac{\dot{u}}{\dot\phi} = -\ell \> \frac{du}{d\p…text/html2014-04-23T20:54:00-08:00book:content:missing
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Non-vacuum Friedmann solutions can be classified using similar methods to those used in the vacuum case. We restrict the discussion here to some special cases. In particular, we assume throughout this section that $\Lambda=0$, which brings Friedmann's equation to the form \begin{equation} \dot{a}^2 = \frac{8\pi\rho a^2}{3} - k \end{equation}text/html2014-04-30T21:54:00-08:00book:content:nutshell
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We summarize here the basic properties of differential forms. See Chapter~12 for further details.
Wedge Products
Differential forms are integrands, the things one integrates. So $dx$ is a differential form (a 1-form), and so is $dx\,dy$ (a 2-form). However, orientation matters; think about change of variables, where for instance \begin{equation} du\,dv = \Jacobian{u}{v}{x}{y} \> dx\,dy \end{equation} where $\Jacobian{u}{v}{x}{y}$ denotes the determinant of the Jacobian matrix of $(u,v)$ w…text/html2013-09-29T10:45:00-08:00book:content:ocircle
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Further information about the possible orbits in the Schwarzschild geometry can be obtained by analyzing the potential more carefully. Using the same conventions as before, we have \begin{equation} \frac12 \dot{r}^2 = \frac{e^2-1}{2} - V \label{rdot} \end{equation} with \begin{equation} V = \frac12\left(1-\frac{2m}{r}\right) \left(1+\frac{\ell^2}{r^2}\right) - \frac12 \end{equation} Differentiating $V$ with respect to $r$ yields \begin{equation} V' = \frac{dV}{dr} = \frac{mr^2-\ell^2r+3m\ell^2…text/html2013-12-17T22:03:00-08:00book:content:onewton
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Figure 1:Newtonian particle trajectories in the gravitational field of a
massive object (heavy dot) can be circular, elliptical, or hyperbolic, all
with the (center of the) gravitational source at one focus. Radial
trajectories are also possible; these are the only trajectories that hit
the source.
How do objects move in Newtonian gravity? We all know that objects in orbit move on ellipses, and that ``slingshot'' hyperbolic trajectories also exist. The various possibilities, also including…text/html2013-12-20T18:15:00-08:00book:content:onull
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We repeat the computations in the previous section for lightlike orbits. We still have \begin{align} \ell &= \Pvec\cdot\vv = r^2 \dot\phi \\ e &= -\Tvec\cdot\vv = \left(1-\frac{2m}{r}\right)\dot{t} \end{align} but now \begin{equation} 0 = \left(1-\frac{2m}{r}\right)\,\dot{t}^2 - \frac{\dot{r}^2}{1-\frac{2m}{r}} - r^2\,\dot\phi^2 \end{equation} which leads to \begin{equation} \dot{r}^2 = e^2 - \left(1-\frac{2m}{r}\right)\frac{\ell^2}{r^2} \label{nullgeo} \end{equation}text/html2013-08-22T17:41:00-08:00book:content:oradial
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Consider now radial geodesics, for which $\ell=0$, so that \begin{equation} \dot{r}^2 = e^2 - \left(1-\frac{2m}{r}\right) \end{equation} A radial geodesic represents a freely falling object with no angular momentum. The energy $e$ determines the radius $r_0$ at which the object is at rest, since if $\dot{r}=0$ at $r=r_0$ then \begin{equation} r_0 = \frac{2m}{1-e^2} \end{equation} Since $r$ must be nonnegative, we must have \begin{equation} e^2 \le 1 \end{equation} and we will assume that $e$ is …text/html2013-12-12T10:08:00-08:00book:content:orbits
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In (ss)~Newtonian Motion and (ss)~Schwarzschild Geodesics, we have seen that the trajectory of an object moving in the gravitational field of a point mass is controlled by the object's energy per unit mass ($e=E/M$), and its angular momentum per unit mass ($\ell=L/M$). In the Newtonian case, we have \begin{equation} \frac12 \dot{r}^2 = e - \left(-\frac{m}{r} + \frac{\ell^2}{2r^2}\right) \label{rdotn} \end{equation} from Equation~(11) of (ss)~Newtonian Motion (where we have set $G=1$), and in…text/html2014-04-23T15:42:00-08:00book:content:penrose
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A Penrose diagram is a spacetime diagram in which points at infinity are included. This is accomplished by rescaling the metric, that is, replacing $ds^2$ by $\Omega^2\,ds^2$, where the conformal factor $\Omega$ typically behaves like \begin{equation} \Omega \sim \frac{1}{r} \end{equation} Points with $\Omega=0$ therefore correspond to points ``at infinity''; more formally, this construction adds a conformal boundary to the original spacetime. Since the metric has merely been rescaled by the c…text/html2013-05-11T21:16:00-08:00book:content:preface
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This book is an introduction to general relativity, intended for advanced undergraduates or beginning graduate students in either mathematics or physics. The goal is to describe some of the surprising implications of relativity without introducing more formalism than necessary. ``Necessary'' is of course in the eye of the beholder, and this book takes a nonstandard path, using differential forms rather than tensor calculus, and trying to minimize the use of ``index gymnastics'' as much as poss…text/html2013-08-02T21:25:00-08:00book:content:prereqs
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Figure 7:A hyperbolic triangle showing the hyperbolic angle between shell
observers and rain observers.
We digress briefly to introduce ``rain'' coordinates adapted to freely falling observers who start from rest at $r=\infty$, each of whom moves along a geodesic as described in the preceding section. As shown there, a shell observer sees such observers fall past them with speed \begin{equation} \tanh\beta = -\sqrt{\frac{2m}{r}} \end{equation} Drawing a right triangle to these proportions, as …text/html2013-10-31T18:25:00-08:00book:content:raincon
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Recall from (ss)~Rain Coordinates that \begin{align} \sigma^T &= dt + \frac{\sqrt{\frac{2m}{r}}}{1-\frac{2m}{r}} \>dr \\ \sigma^R &= \frac{dr}{1-\frac{2m}{r}} + \sqrt{\frac{2m}{r}} \>dt \end{align} which allows us to introduce rain coordinates ($T$,$R$) defined by \begin{align} dT &= dt + \sqrt{\frac{2m}{r}}\frac{dr}{1-2m/r} \\ dR &= \sqrt{\frac{r}{2m}}\frac{dr}{1-2m/r} + dt \end{align} The Schwarzschild line element in rain coordinates then takes the form \begin{equation} ds^2 = -dT^2 + \frac{…text/html2014-04-24T10:09:00-08:00book:content:raincurv
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A useful technique in exploring an unknown geometry is to follow light beams, which leads to the use of null coordinates. Equivalently, factor the line element.
In Minkowski space, we have \begin{equation} ds^2 = dx^2 - dt^2 = (dx+dt)(dx-dt) \end{equation} Thus, introduce coordinates \begin{align} u &= t-x \\ v &= t+x \end{align} which brings the line element to the form \begin{equation} ds^2 = -du\,dv \end{equation} Why are null coordinates useful? Because the surfaces (curves) along which $…text/html2014-04-23T15:43:00-08:00book:content:rindgeo
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Taking the ``square root'' of the line element, we have \begin{equation} d\rr = \rho\,d\alpha\,\Ahat + d\rho\,\Rhat \end{equation} where \begin{align} \Ahat\cdot\Ahat &= -1 \\ \Rhat\cdot\Rhat &= 1 \\ \Ahat\cdot\Rhat &= 0 \end{align} Since the line element depends only on $\rho$, but not on $\alpha$, there is a Killing vector \begin{equation} \Avec = \rho\,\Ahat \end{equation} since \begin{equation} \Avec\cdot\grad f = \Partial{f}{\alpha} \end{equation} (and of course $\grad f\cdot d\rr=df$). …text/html2013-12-12T09:23:00-08:00book:content:rindler
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We digress briefly from our discussion of the Schwarzschild geometry in order to consider a much simpler geometry with many of the same properties.
Figure 1: The shaded region is the Rindler wedge in Minkowski space, which
is covered by the Rindler coordinates ($\rho$,$\alpha$).text/html2013-12-17T22:04:00-08:00book:content:rindprop
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What do Rindler coordinates represent? Consider a worldline with $\rho=\hbox{constant}$, as shown in Figure~1. Since $x^2-t^2=\hbox{constant}$, this worldline is a timelike hyperbola, and is in fact one of our calibrating hyperbolas from special relativity, at constant ``distance'' $\rho$ from the origin.text/html2013-12-19T12:01:00-08:00book:content:rn
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Assuming a spherically symmetric line element of the form \begin{equation} ds^2 = -f\,dt^2 + \frac{dr^2}{f} + r^2\,d\theta^2 + r^2\sin^2\theta\,d\phi^2 \end{equation} where $f$ is an arbitrary function of $r$, Einstein's equation with an electromagnetic source, representing a point charge, can be solved for $f$, yielding \begin{equation} f = 1 - \frac{2m}{r} + \frac{q^2}{r^2} \end{equation} The resulting spacetime is known as the Reissner-Nordstr\"om geometry, and represents a black hole with…text/html2019-05-26T16:33:37-08:00book:content:rw
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We now study simple models of the universe, and therefore assume both homogeneity and isotropy. As discussed in~(ss)Cosmological Principle, homogeneity implies that spacetime is foliated by spacelike hypersurfaces $\Sigma_t$; isotropy implies there are preferred ``cosmic observers'' orthogonal to these hypersurfaces. Thus, each $\Sigma_t$ represents an instant of time according to these cosmic observers. We can therefore assume without loss of generality that the surfaces are labeled using …text/html2013-12-18T09:15:00-08:00book:content:rwcurv
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The Robertson-Walker line element is \begin{align} ds^2 &= -dt^2 + a(t)^2 \Biggl( \frac{dr^2}{1-kr^2} \Biggr.\nonumber\\ &\qquad\Biggl.{} + r^2 \left( d\theta^2 + \sin^2\theta\,d\phi^2 \right) \Biggr) \end{align} It now follows immediately that \begin{align} d\rr &= dt\,\That + \frac{a(t)\,dr}{\sqrt{1-\kappa r^2}}\,\rhat + a(t)\,r\,d\theta\,\that + a(t)\,r\,\sin\theta\,d\phi\,\phat \end{align} and the basis 1-forms are \begin{align} \sigma^t &= dt \\ \sigma^r &= \frac{a(t)\,dr}{\sqrt{1-…text/html2014-04-23T15:45:00-08:00book:content:schwarz
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The Schwarzschild geometry is described by the line element \begin{equation} ds^2 = -\left(1-\frac{2m}{r}\right)\,dt^2 + \frac{dr^2}{1-\frac{2m}{r}} \\ + r^2\,d\theta^2 + r^2\sin^2\theta\,d\phi^2 \label{schwmet} \end{equation} As we will see later, this metric is the unique spherically symmetric solution of Einstein's equation in vacuum, and describes the gravitational field of a point mass at the origin. Yes, it also describes a black hole, but this was not realized for nearl…text/html2013-10-31T22:26:00-08:00book:content:schwcon
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We have so far related curvature to geodesic deviation by working in rain coordinates, a special coordinate system adapted to the radial geodesics we chose to study. But this relationship is geometric, and therefore independent of the coordinates we choose. To demonstrate this geometric invariance, we revisit the problem of geodesic deviation using our original Schwarzschild coordinates. First, we need the connection.text/html2015-05-19T19:20:00-08:00book:content:schwcurv
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The Schwarzschild line element is \begin{equation} ds^2 = -f\,dt^2 + \frac{dr^2}{f} + r^2\,d\theta^2 + r^2\sin^2\theta\,d\phi^2 \end{equation} where we have written $f$ for the function \begin{equation} f(r) = 1-\frac{2m}{r} \end{equation} with derivatives \begin{align} f' &= \frac{df}{dr} = \frac{2m}{r^2} \\ \fpp &= -\frac{4m}{r^3} \end{align} It now follows immediately that \begin{equation} d\rr = \sqrt{f}\,dt\,\That + \frac{dr}{\sqrt{f}}\,\rhat + r\,d\theta\,\that + r\,\sin\theta\,d\phi\,\ph…text/html2014-04-23T15:41:00-08:00book:content:schwext
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We now apply the same technique used in Chapter~ in (ss)~Rindler, to extend the Rindler geometry to the Schwarzschild geometry. Consider a radial light beam, so that $d\phi=0$ (and as usual $\theta=\pi/2$). Then the line element becomes
\begin{equation} ds^2 = -\left(1-\frac{2m}{r}\right)\,dt^2 + \frac{dr^2}{1-\frac{2m}{r}} = -\left(1-\frac{2m}{r}\right) \left( dt^2 - \frac{dr^2}{\left(1-\frac{2m}{r}\right)^2} \right) \end{equation} which we can factor as \begin{equation} ds^2 = -\…text/html2013-12-17T22:01:00-08:00book:content:schwgeo
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A fundamental principle of general relativity is that freely falling objects travel along timelike geodesics. So what are those geodesics?
Taking the square root of the line element, the infinitesimal vector displacement in the Schwarzschild geometry is \begin{equation} d\rr = \sqrt{1-\frac{2m}{r}}\,dt\,\That + \frac{dr\,\rhat}{\sqrt{1-\frac{2m}{r}}} + r\,d\theta\,\that + r\sin\theta\,d\phi\,\phat \label{drschw} \end{equation} where \begin{align} \That\cdot\That &= -1 \\ \rhat\cdot\rhat &= 1…text/html2014-04-23T15:42:00-08:00book:content:schwgeom
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The basic features of the Schwarzschild geometry are readily apparent by examining the metric.
\begin{itemize}\item Asymptotic Flatness:
As already discussed, the Schwarzschild geometry reduces to that of Minkowski space as $r$ goes to infinity. \itemSpherical Symmetry:
The angular dependence of the Schwarzschild metric is precisely the same as that of a sphere; the Schwarzschild geometry is spherically
symmetric. It is therefore almost always sufficient to consider the equatorial plane …text/html2014-04-23T15:47:00-08:00book:content:schwobs
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An observer is really an army of observers stationed at all points in space. More formally, the worldlines of a family of observers foliate the spacetime. Each observer records what he or she sees, and the resulting logs are later compared. This process is often loosely described as ``an observer seeing''; a better description would be ``a family of observers recording''.text/html2013-12-18T08:18:00-08:00book:content:standard
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Figure 1:The expansion of the Einstein-de Sitter cosmology.
Figure 2:The expansion of the dust-filled Robertson-Walker cosmology.
Figure 3:The hyperbolic analog of the dust-filled Robertson-Walker cosmology.
Figure 4:The expansion of the radiation-filled Robertson-Walker cosmology.
The standard cosmological models are models without cosmological constant ($\Lambda=0$). We first consider Friedmann models ($p=0$), for which \begin{equation} \dot{a}^2 = \frac{C}{a} - k \end{equation} If $k=…text/html2014-04-30T21:47:00-08:00book:content:symmetries
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As discussed in the previous section, geodesics are the solutions to a system of second-order differential equations. These equations are not always easy to solve; solving differential equations is an art form. However, dramatic simplifications occur in the presence of symmetries, as we now show.text/html2014-04-30T21:51:00-08:00book:content:sympolar
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In polar coordinates, we have \begin{equation} d\rr = dr\,\rhat + r\,d\phi\,\phat \end{equation} and the line element is \begin{equation} ds^2 = dr^2 + r^2\,d\phi^2 \end{equation} Both of these expressions depend explicitly on $r$, but not $\phi$. Thus, the line element does not change in the $\phi$ direction, and we expect ``$\Partial{}{\phi}$'' to be a Killing vector. But what vector is this?text/html2014-04-30T21:50:00-08:00book:content:symsphere
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On the sphere, we have \begin{equation} d\rr = r\,d\theta\,\that + r\sin\theta\,d\phi\,\phat \end{equation} and the line element is \begin{equation} ds^2 = r^2\,d\theta^2 + r^2\,\sin^2\theta\,d\phi^2 \end{equation} Both of these expressions depend explicitly on $\theta$, but not $\phi$ (or $r$, which is constant). Thus, the line element does not change in the $\phi$ direction, and we again expect ``$\Partial{}{\phi}$'' to be a Killing vector.text/html2014-04-30T21:40:00-08:00book:content:symthm
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We show here that coordinate directions in which the metric (line element) doesn't change always correspond to Killing vectors.
Theorem: Suppose that $\{x=y^0,y^1,...\}$ are orthogonal coordinates, so that \begin{equation} d\rr = h\,dx\,\xhat + \sum\limits_i h_i\,dy^i\,\yhat{}^i \end{equation} and suppose further that the coefficients $h=h_0,h_1,...$ do not
depend on $x$, that is, suppose that \begin{equation} \Partial{h}{x} = 0 = \Partial{h_i}{x} \end{equation} Then $\XX = h\xhat$ is a Kill…text/html2014-04-23T18:27:00-08:00book:content:tensors
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~~~~~~~~~~~~~ ~
Figure 1: Nearby objects falling radially, either next to each other (at equal
radius), or directly on top of each other.
Consider two nearby objects falling radially. We first consider the case where both objects start at rest on the same $r=\hbox{constant}$ shell, so that they have the same energy $e$. This situation is shown in the first diagram in Figure~1. The separation between the objects is therefore \begin{equation} \Delta s = r \,\Delta\phi \end{equation} and …text/html2014-04-23T20:02:00-08:00book:content:tidal2
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The components $R^i{}_{jk\ell}$ of the curvature 2-forms form a tensor, known as the Riemann curvature tensor. Tensor components can be computed in any basis, then converted to any other basis using the appropriate change-of-basis transformations. Put differently, tensors are linear maps on vectors, and can therefore easily be evaluated on any vectors, not just on basis vectors.