A Bernoulli first-order ode has the form
where g(t) and h(t) are given functions and n does not equal 1.
Solution Procedure
The idea is to convert the Bernoulli equation into a linear ode. We make the substitution
Differentiating this expression we have
Solving for y'(t), we have
Substituting this expression into the original ode (*), we have
Dividing both sides by y^n/(1-n) we have
Replacing y^(1-n) by v, we obtain
This is a linear ode in v(t)! Solve for v(t). We obtain y(t) using the formula
Example
Consider the ode
This is a Bernoulli equation with n=3, g(t)=5, h(t)=-5t. We make the substitution
Applying the chain rule, we have
Solving for y'(t), we have
Substituting for y'(t) in the differential equation we have
Dividing both sides by -.5y^3, we have
Note that 1/y^2=v. Hence, we have
This is a linear ode for the dependent variable v(t). The solution is
where C is a constant. Substiting v=1/y^2, we have
[ODE Home] [1st-Order Home] [2nd-Order Home] [Laplace Transform Home] [Notation] [References]
Copyright © 1996 Department of Mathematics, Oregon State University
If you have questions or comments, don't hestitate to contact us.